You are given a string and two markers (the initial one and final). You have to find a substring enclosed between these two markers. But there are a few important conditions.
This is a simplified version of the Between Markers mission.
- The initial and final markers are always different.
- The initial and final markers are always 1 char size.
- The initial and final markers always exist in a string and go one after another.
Input: Three arguments. All of them are strings. The second and third arguments are the initial and final markers.
Output: A string.
Example:
between_markers('What is >apple<', '>', '<') == 'apple'
1
How it is used: For text parsing.
Precondition: There can't be more than one final and one initial markers.
-> Solve it
def between_markers(text: str, begin: str, end: str) -> str:
"""
#returns substring between two given markers
"""
return text[text.index(begin)+1:text.index(end)]
def between_markers(text: str, begin: str, end: str) -> str:
"""
#returns substring between two given markers
"""
return text[text.index(begin)+1:text.index(end)]
if __name__ == '__main__':
print('Example:')
print(between_markers('What is >apple<', '>', '<'))
# These "asserts" are used for self-checking and not for testing
assert between_markers('What is >apple<', '>', '<') == "apple"
assert between_markers('What is [apple]', '[', ']') == "apple"
assert between_markers('What is ><', '>', '<') == ""
assert between_markers('>apple<', '>', '<') == "apple"
print('Wow, you are doing pretty good. Time to check it!')
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